Pertanyaan :
1. Gerbang AND, table dan gambar!
2. 3A₍₁₆₎ = … ₍₁₀₎
3. A341₍₁₆₎ = … ₍₁₀₎
4. 25₍₁₀₎ = … ₍₂₎
5. 73₍₁₀₎ = … ₍₈₎
6. BC₍₁₆₎ = … ₍₂₎
7. 1011₍₂₎ + 0101₍₂₎ = … ₍₂₎
8. 10100110 AND 01110101 = … ₍₂
₎
9. 11010110 NAND AB₍₁₆₎ = … ₍₂₎
10. 7456₍₁₆₎ + 7878₍₁₆₎ = … ₍₁₆₎
11. 101.11₍₂₎ = … ₍₁₀₎
Jawaban :
1. Gebang AND.
2. 3A₍₁₆₎ = (3 x 16¹) + (10 x 16⁰)
= 48 + 10
= 58
3. A341₍₁₆₎ = (10 x 16³) + (3 x 16²) + (4 x 16¹) + (1 x 16⁰)
= 40960 + 768 + 64 + 1
= 41763
4. 25 : 2 = 12 sisa 1
12 : 2 = 6 sisa 0
6 : 2 = 3 sisa 0
3 : 2 = 1 sisa 1
jadi hasilnya adalah 11001
5. 73 : 8 = 9 sisa 1
9 : 8 = 1 sisa 1
jadi hasilnya adalah 111
6. BC ₍₁₆₎ = 10111100 ₍₂₎
8 4 2 1
11 = 1 0 1 1
12 = 1 1 0 0
Jadi BC bernilai 10111100
7. 1 0 1 1
0 1 0 1 +
10000
8.1 0 1 0 0 1 1 0
0 1 1 1 0 1 0 1 AND
0 0 1 0 0 1 0 0
9. AB₍₁₆₎ = (10 × 16¹) + (11 × 16⁰)
= 160 + 11
= 171
171 : 2 = 85 sisa 1 => 1 1 0 1 0 1 1 0
85 : 2 = 42 sisa 1 1 0 1 0 1 0 1 1 AND
42 : 2 = 21 sisa 0 1 0 0 0 0 0 1 0 NOT
21 : 2 = 10 sisa 1 0 1 1 1 1 1 0 1
10 : 2 = 5 sisa 0 jadi hasilnya adalah 0 1 1 1 1 1 0 1
5 : 2 = 2 sisa 1
2 : 2 = 1 sisa 0
10101011
10. 7 4 5 6
7 8 7 8 +
E C C E
11. 101.11 = (1 × 2²) + (1 × 2⁰) + ( 1 × 2¯¹) + ( 1 × 2¯²)
= 4 + 1 + ½ + ¼
= 4 + 1 + 0,5 + 0,25
= 5,75
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